# How To Solve A Rate Problem

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We can also see that 3/12 will yield .25, so 3/13 will be slightly lower. If moving toward or away from each other, we can add their speeds to see their relative velocities. Notice that: Train A = 9 hours at 60 miles/hour = 540 miles Train B = 6 hours at 90 miles/hour = 540 miles We can now tackle Train C, which has traveled the same time as B (6 hours), and traveled (1260 – 540) miles.

At this point, we may not be able to decide between (D) or (E). Because the denominator is 13, we know the decimal cannot equal .25. When moving at an angle, we may be looking at a geometry question. If all three trains meet at the same time between New York and Dallas, what is the speed of Train C if the distance between Dallas and New York is 1260 miles? So when they all meet up, the time will be 3am, and they will be at mile marker 540.

An object is said to be in uniform motion when it moves without changing its speed.

All this means is that we can find the distance an object travels as long as we know the object is moving at a constant (fixed) speed or pace or at an average rate or speed.

When together, they will complete 1/6 1/7 trucks/ 1 hour.1/6 1/7 = 6/42 7/42 = 13/42 trucks/1 hour. This means that B will gain on A at a rate of 30 miles every hour.

180 m/hr Relative to Train A, Train B’s velocity is 30 m/hr.

In this section we are going to look at an application of implicit differentiation.

Most of the applications of derivatives are in the next chapter however there are a couple of reasons for placing it in this chapter as opposed to putting it into the next chapter with the other applications.

A.3.a Make tables of equivalent ratios relating quantities with whole-number measurements, find missing values in the tables, and plot the pairs of values on the coordinate plane.

For example, if it took 7 hours to mow 4 lawns, then at that rate, how many lawns could be mowed in 35 hours?

## Comments How To Solve A Rate Problem

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